Pump Flow Rate (GPM) Calculator

Calculate the required pump flow rate in GPM from irrigated acres, application depth, and available pumping hours. Size your irrigation pump correctly.

ac
in
hrs
ft
$/kWh
Required Flow Rate
786 GPM
1.75 CFS | 47,142 GPH
Total Volume
3,394,250 gal
125.0 ac-in | 10.42 ac-ft
Pipe Velocity
5.0 ft/s
Within optimal range (2-8 ft/s)
Water Horsepower
15.9 WHP
At 80 ft TDH
Brake Horsepower
22.7 BHP
70% pump efficiency (Centrifugal (surface))
Motor Size Needed
25 HP
16.9 kW equivalent
Energy Cost/Hour
$1.69
$122.00 total for 72 hrs
Cost Per Acre
$0.97
$0.97/ac-in

Pipe Velocity Check

Too slow (<2)5.0 ft/s in 8-inch pipeToo fast (>8)

Power & Cost Breakdown

Water HP15.9 HP
Brake HP22.7 HP
Motor HP (rated)25.0 HP
Pipe Size & Flow Rate Reference
Pipe Dia (in)Max GPMOptimal GPMStatus
24520-35-
310050-80-
4180100-150-
6450250-350-
8 *800500-650OK
101,250800-1000OK
121,8001200-1500OK
Planning notes, formulas, and examples

About the Pump Flow Rate (GPM) Calculator

Selecting the right pump capacity is critical for irrigation system design. The required flow rate (GPM) depends on the area to be irrigated, the depth of water applied per irrigation event, and the hours available to complete the application.

The formula converts irrigated acres and application depth into a total volume, then divides by available pumping time to get the required flow rate. The constant 452 accounts for unit conversions between acres, inches, gallons, and minutes.

This page converts acres, depth, and run time into the GPM target the pumping plant actually has to meet.

When This Page Helps

The key question is whether the pump can finish the set in the available window. This page frames the answer in GPM rather than rough rules of thumb.

How to Use the Inputs

  1. Enter the number of irrigated acres.
  2. Enter the target application depth in inches per irrigation.
  3. Enter the hours available to complete one irrigation cycle.
  4. Read the required pump flow rate in GPM.
  5. Compare with your well's tested yield to verify capacity.
Formula used
GPM = (Acres ร— Depth (in) ร— 452) / Hours Available Where 452 = 27,154 gal/ac-in รท 60 min/hr

Example Calculation

Result: Required GPM = 785

GPM = (125 ร— 1.0 ร— 452) / 72 = 56,500 / 72 = 785 GPM. A well yielding 800+ GPM is needed to irrigate this quarter-section pivot at one inch per 3-day rotation.

Tips & Best Practices

  • Standard quarter-section pivots require 700โ€“900 GPM at 1 in per 3-day rotation.
  • If your well yield is less than required GPM, reduce acreage or extend cycle time.
  • Include system efficiency in the depth: use gross depth, not net.
  • Peak-season demand sets the pump sizing requirement; early/late season is lower.
  • Multiple wells can feed one pivot to reach the required GPM.
  • Account for 10โ€“15% decline in well yield over the pump's life.

System Capacity and Peak Demand

Peak irrigation demand typically occurs in July and August for the central U.S. Design your pump for peak conditions, then throttle back during lower-demand periods. A VFD (variable-frequency drive) lets you adjust flow without inefficiency.

Well Yield vs Required GPM

Well yield declines over time as well screens clog or the aquifer declines. Build in a 10โ€“20% margin above calculated GPM to account for future yield reduction. Monitoring well drawdown annually detects problems early.

Multiple-Well Systems

When one well cannot supply enough GPM, two or more wells can feed a common mainline. Each well's flow is additive, but consider drawdown interference if wells are close together. A spacing of at least 500โ€“1,000 ft between wells minimizes interference.

Sources & Methodology

Last updated:

Frequently Asked Questions

  • It combines the conversion from acre-inches to gallons (1 ac-in = 27,154 gal) and from hours to minutes (60 min/hr). 27,154 / 60 = 452.6, rounded to 452.