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Calculate the orbital period for any body orbiting a central mass. Includes solar system verification, unit conversions, and binary system mode.
| Body | Distance (m) | Actual (days) | Calculated (days) | Error |
|---|---|---|---|---|
| Mercury | 5.791e+10 | 87.97 | 87.96 | 0.01% |
| Venus | 1.082e+11 | 224.70 | 224.64 | 0.03% |
| Earth | 1.496e+11 | 365.25 | 365.21 | 0.01% |
| Mars | 2.279e+11 | 687.00 | 686.69 | 0.04% |
| Jupiter | 7.786e+11 | 4,332.60 | 4,336.28 | 0.08% |
| Saturn | 1.434e+12 | 10,759.00 | 10,838.51 | 0.74% |
| Moon | 3.844e+8 | 27.32 | 27.45 | 0.48% |
| ISS | 6.771e+6 | 0.06 | 0.06 | 0.43% |
| Unit | Value |
|---|---|
| Seconds | 31,554,187.75 |
| Minutes | 525,903.1291 |
| Hours | 8,765.0522 |
| Days | 365.210506 |
| Years | 0.999875 |
The orbital period is the time it takes for a celestial body to complete one full orbit around another body. It is determined by the mass of the central body and the orbital distance, following directly from Kepler's Third Law generalized by Newton: T = 2π√(a³/GM).
From the 92-minute orbit of the International Space Station to the 165-year orbit of Neptune, orbital periods span an extraordinary range. Understanding how period relates to distance and mass is essential for satellite engineering, space mission planning, and exoplanet characterization.
This calculator computes the orbital period from the central body's mass and the orbital distance, supports multiple mass and distance units, handles binary systems, and verifies results against the known orbital periods of all solar system planets and the Moon. An interactive comparison chart and period unit conversion table provide additional context.
It gives orbital period computations for any gravitational system, from Earth satellites to exoplanets. The built-in solar system verification table and multiple unit options make it both a learning tool and a practical reference for students, engineers, and astronomy enthusiasts.
Orbital period: T = 2π × √(a³ / (GM)), where T is the period in seconds, a is the semi-major axis in meters, G = 6.674 × 10⁻¹¹ m³/(kg·s²), and M is the central body mass in kilograms. Orbital velocity: v = 2πa / T.Result: Period ≈ 92.4 minutes
The ISS orbits at about 6,771 km from Earth's center (400 km altitude). At this distance, the orbital period is about 92 minutes, completing ~15.5 orbits per day.
Calculate the orbital period for any body orbiting a central mass. Includes solar system verification, unit conversions, and binary system mode. Use it when you need a repeatable calculation in the physics / astronomy category and want the setup, result, and supporting values kept together. This is especially helpful when small input changes, unit choices, or rounding decisions can change the final number.
Start by confirming that the inputs match the formula shown on the page. Then compare the main output with the worked example and any secondary values shown by the calculator. If the result will be used in another calculation, keep extra precision until the final step and record the assumptions beside the number.
Treat the result as a calculation aid rather than a substitute for context. For schoolwork, include the formula and substitution steps. For planning, technical, financial, or health-related decisions, verify important numbers against primary records, current rules, or a qualified professional before acting on them.
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Two factors: the mass of the central body and the orbital distance. Greater mass means a shorter period at the same distance, and greater distance means a longer period around the same mass.
For most practical cases no — only the central body mass matters. For binary systems where both masses are comparable, the total system mass is used.
An orbit with a period of exactly 24 hours (86,400 seconds) at about 35,786 km altitude above Earth's equator. Satellites in this orbit appear stationary from the ground.
At just 400 km altitude (6,771 km from Earth's center), the ISS is close enough that Earth's. gravity produces a very short orbital period of about 92 minutes.
Yes. Enter the host star's mass in solar masses and the orbital distance in AU to compute any exoplanet's orbital period.
No. The orbital period depends only on the semi-major axis, not the eccentricity. A circular and a highly elliptical orbit with the same semi-major axis have the same period.
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