Thermal Resistance Calculator

Calculate thermal resistance for up to 6 stacked layers. Includes temperature profile, layer breakdown, heat flux, status indicator, and presets for CPU, LED, and MOSFET thermal paths.

W
°C

Thermal Layers (hot side → cold side)

Layer 1
mm
mm²
Total Thermal Resistance
0.0025 °C/W
1 layer in series
Temperature Rise (ΔT)
0.02 °C
ΔT = R_th × P = 0.002 × 10
Hot Side Temperature
25.02 °C
25 °C + 0.02 °C
Thermal Conductance
401.0000 W/°C
G = 1/R_th
Heat Flux
1.00 W/cm²
At first layer area
Status
✓ OK
Peak 25.0 °C within safe range

Temperature Profile

Hot side25.0 °C
Ambient25.0 °C

Layer Breakdown

LayerR_th (°C/W)ΔT (°C)% of Totalk (W/m·K)
Copper (1.00 mm)0.00250.02
100.0%
401.0
Total0.00250.02100%
Planning notes, formulas, and examples

About the Thermal Resistance Calculator

Thermal resistance (R_th) quantifies how much temperature rise occurs per watt of heat dissipated through a material: ΔT = R_th × P. For a slab of thickness t, area A, and thermal conductivity k, the thermal resistance is R_th = t / (kA), measured in °C/W. When multiple layers are stacked in series — as in a chip-to-heatsink assembly — the total thermal resistance is the sum of each layer's contribution.

Proper thermal management is critical in electronics: exceeding a component's maximum junction temperature causes performance degradation, reduced lifetime, or immediate failure. The path from a semiconductor die to ambient air may include a die attach layer, thermal paste, heatsink base, and fins — each contributing to the total thermal resistance.

This calculator lets you model up to 6 stacked thermal layers, each with independent material, thickness, and area. It computes the total thermal resistance, temperature at each interface, heat flux, and a visual temperature profile so you can identify thermal bottlenecks.

When This Page Helps

Thermal stack-ups involve multiple materials with very different conductivities (copper at 401 W/m·K vs. FR4 at 0.25 W/m·K), so a thin layer of poor conductor can dominate the total thermal resistance. This calculator identifies which layer is the bottleneck and shows the temperature at every interface — information that would require tedious manual calculation for multi-layer assemblies.

How to Use the Inputs

  1. Enter the total power dissipated through the thermal path in watts.
  2. Set the ambient (cold side) temperature.
  3. Configure each thermal layer: select a material, enter thickness (mm) and cross-section area (mm²).
  4. Add layers with the + button (up to 6 in series, ordered hot side → cold side).
  5. Use presets for common thermal assemblies like CPU-to-heatsink or LED-on-PCB.
  6. Read the temperature profile to see where the largest temperature drops occur.
  7. Optimize by replacing the highest R_th layer with a better conductor or larger area.
Formula used
Single Layer: R_th = t / (k × A) Series Stack: R_total = R₁ + R₂ + … + Rₙ Temperature Rise: ΔT = R_total × P Junction Temperature: T_j = T_ambient + ΔT Heat Flux: q = P / A (W/m²) Thermal Conductance: G = 1 / R_th (W/°C) Where: t = thickness (m) k = thermal conductivity (W/m·K) A = cross-section area (m²) P = power dissipation (W)

Example Calculation

Result: T_j = 49.3 °C

For a CPU dissipating 125 W: the thermal paste layer (0.1 mm, 1600 mm², k=5) has R_th = 0.0001/(5 × 0.0016) = 0.0125 °C/W. The aluminum base (10 mm, 10000 mm², k=237) has R_th = 0.01/(237 × 0.01) = 0.0042 °C/W. Total R_th = 0.0167 °C/W. ΔT = 0.0167 × 125 = 2.09 °C. T_j = 25 + 24.3 = 49.3 °C (well within limits).

Tips & Best Practices

  • The thinnest layer of the worst conductor often dominates thermal resistance — even 0.1 mm of thermal paste can matter more than 10 mm of aluminum.
  • Increasing the cross-section area reduces thermal resistance proportionally — wider heatsink bases and larger thermal pads help significantly.
  • Contact resistance (gaps and surface roughness) adds thermal resistance not captured by bulk conductivity alone — use thermal paste to fill microscopic air gaps.
  • For forced-air cooling, the convection resistance of the heatsink fins (typically 0.5-5 °C/W) must be added to the conduction stack.
  • Common maximum junction temperatures: silicon ICs 125 °C, LEDs 80-120 °C, power MOSFETs 150-175 °C.
  • If using a thermal pad instead of paste, check its thickness under clamping pressure — compressed pads have lower effective thickness and better performance.

Thermal Management in Electronics

Modern processors can dissipate over 300 W in a package smaller than a postage stamp, creating heat flux densities exceeding 100 W/cm². Managing this heat requires careful attention to every layer in the thermal path: die attach, thermal interface material (TIM), heatsink base, and fin array. Each layer contributes thermal resistance, and the total determines whether the chip stays within its safe operating temperature.

Thermal Interface Materials (TIMs)

TIMs bridge the microscopic air gaps between two mating surfaces. Categories include thermal greases (k = 1-12 W/m·K), phase-change materials (soften at operating temperature for better contact), thermal pads (convenient but higher R_th), and liquid metal (k = 20-70 W/m·K but electrically conductive and corrosive). The choice depends on the application requirements: ease of rework, electrical isolation, and maximum temperature.

Advanced Thermal Design

For high-performance systems, engineers use copper heat pipes (effective k > 10,000 W/m·K), vapor chambers, thermoelectric coolers (Peltier devices), and direct-die liquid cooling. These technologies reduce effective thermal resistance far below what solid conduction alone can achieve, enabling processors to boost to higher frequencies while staying within thermal limits.

Sources & Methodology

Last updated:

Frequently Asked Questions

  • Thermal conductivity (k, in W/m·K) is a material property — how well the material conducts heat. Thermal resistance (R_th, in °C/W) depends on the specific geometry (thickness and area). A highly conductive material in a thin, wide layer has very low thermal resistance.