Air Pressure at Altitude Calculator
Calculate atmospheric pressure, temperature, and air density at any altitude using the International Standard Atmosphere (ISA) model. Supports humidity correction.
Calculate hydraulic radius Rh = A/P and hydraulic diameter Dh = 4A/P for circular, rectangular, trapezoidal, and triangular cross-sections.
| Variant | Area (m²) | Perimeter (m) | Rh (m) | Dh (m) |
|---|---|---|---|---|
| 25% | 0.01382 | 0.3142 | 0.04399 | 0.1760 |
| 50% | 0.03534 | 0.4712 | 0.07500 | 0.3000 |
| 75% | 0.05687 | 0.6283 | 0.09051 | 0.3620 |
| 100% | 0.07069 | 0.9425 | 0.07500 | 0.3000 |
The hydraulic radius is a fundamental geometric property used throughout fluid mechanics. Defined as the ratio of cross-sectional flow area to wetted perimeter (Rh = A/P), it characterizes how efficiently a channel shape conveys flow. The closely related hydraulic diameter Dh = 4A/P = 4Rh is used to substitute non-circular cross-sections into pipe-flow equations like Darcy–Weisbach and the Reynolds number.
For a full circular pipe, Rh = D/4 and Dh = D, which is why the hydraulic diameter collapses to the actual diameter. For non-circular ducts — rectangular, trapezoidal, annular — Dh provides the equivalent pipe diameter for friction and heat-transfer calculations. In open channels, the wetted perimeter excludes the free surface, so only the submerged walls count.
This calculator supports five cross-section types: circular (with partial fill), rectangular, trapezoidal, triangular, and custom (direct A and P entry). The fill-level feature for circular pipes is especially useful for sanitary sewer and stormwater design, where pipes rarely run full.
Hydraulic radius and diameter are needed for every pipe, duct, and channel calculation — from pressure-drop estimates in rectangular HVAC ducts to stormwater design in trapezoidal ditches. This calculator handles all common shapes and partial-fill conditions.
Hydraulic Radius: Rh = A / P
Hydraulic Diameter: Dh = 4A / P = 4 Rh
Full circular pipe: Rh = D/4, Dh = D
Rectangular (open top): P = 2h + w, A = wh
Trapezoidal: A = (b + T)/2 × h, P = b + 2√(h² + ((T−b)/2)²)Result: Rh = 0.075 m, Dh = 0.3 m
A = π/4 × 0.3² = 0.07069 m². P = π × 0.3 = 0.9425 m. Rh = 0.07069 / 0.9425 = 0.075 m. Dh = 4 × 0.075 = 0.3 m (equals the actual diameter).
Calculate hydraulic radius Rh = A/P and hydraulic diameter Dh = 4A/P for circular, rectangular, trapezoidal, and triangular cross-sections. Use it when you need a repeatable calculation in the physics / fluid category and want the setup, result, and supporting values kept together. This is especially helpful when small input changes, unit choices, or rounding decisions can change the final number.
Start by confirming that the inputs match the formula shown on the page. Then compare the main output with the worked example and any secondary values shown by the calculator. If the result will be used in another calculation, keep extra precision until the final step and record the assumptions beside the number.
Treat the result as a calculation aid rather than a substitute for context. For schoolwork, include the formula and substitution steps. For planning, technical, financial, or health-related decisions, verify important numbers against primary records, current rules, or a qualified professional before acting on them.
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The factor of 4 makes Dh equal to the actual diameter for a full circular pipe: D = 4 × (πD²/4)/(πD) = D. This convention simplifies substitution into standard pipe-flow equations.
No. The wetted perimeter includes only surfaces in contact with the fluid. In an open channel, the top (air–water interface) is excluded.
Interestingly, a circular pipe achieves its maximum Rh at about 81% fill — not at 100%. This is because the wetted perimeter grows faster than the area near the top of the circle.
For non-circular cross-sections, Re = ρVDh/μ, where Dh replaces the pipe diameter. This gives the same friction factor from the Moody chart (approximately).
For a given area, a semicircle has the least wetted perimeter and thus the highest Rh. Among practical shapes, a wide-and-shallow trapezoidal channel is more efficient than a deep-and-narrow one.
Yes — Manning's formula v = (1/n) Rh^(2/3) S^(1/2) uses the hydraulic radius directly. It is the standard method for open-channel flow calculations.
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