Air Density Calculator
Calculate air density from pressure, temperature, and humidity using the ideal gas law. Includes altitude reference table and moist air corrections.
Calculate the Biot number to determine if lumped capacitance analysis applies. Compare internal vs external thermal resistance for heat transfer problems.
Green: Bi<0.1 (lumped) · Yellow: 0.1–1 · Red: Bi>1 (distributed)
| h (W/m²K) | Bi | Method |
|---|---|---|
| 5 | 0.0010 | Lumped |
| 10 | 0.0020 | Lumped |
| 25 | 0.0050 | Lumped |
| 50 | 0.0100 | Lumped |
| 100 | 0.0200 | Lumped |
| 500 | 0.1000 | Distributed |
| 1000 | 0.2000 | Distributed |
| Material | k (W/mK) | Bi | Method |
|---|---|---|---|
| Copper | 385 | 0.0013 | Lumped |
| Aluminum | 205 | 0.0024 | Lumped |
| Steel | 50 | 0.0100 | Lumped |
| Glass | 1 | 0.5000 | Distributed |
| Wood | 0.15 | 3.3333 | Distributed |
| Air | 0.026 | 19.2308 | Distributed |
The **Biot Number Calculator** determines whether a heated or cooled body can be treated as thermally uniform (lumped capacitance) or whether internal temperature gradients must be accounted for (distributed analysis with Heisler charts or numerical methods). The Biot number Bi = hLc/k compares convective resistance at the surface to conductive resistance within the body.
When Bi < 0.1, internal conduction is so fast relative to surface convection that the entire body is at nearly the same temperature at all times — lumped capacitance applies. When Bi ≥ 0.1, significant temperature gradients exist inside the body and a more detailed analysis is required.
Enter the convection coefficient (h), material thermal conductivity (k), and characteristic length (Lc), and the calculator categorises the problem and provides the resistance breakdown. Built-in presets cover common engineering scenarios, and the reference tables show how Biot number changes with h and k.
Choosing the wrong analysis method — lumped when distributed is needed, or vice versa — leads to large errors in cooling/heating time predictions. It gives Biot-number classification so you start with the correct approach.
Biot Number: Bi = h Lc / k
Characteristic Length: Lc = V / A (general), half-thickness (plate), r/2 (cylinder), r/3 (sphere)
where h = convection coefficient, k = thermal conductivity, V = volume, A = surface area.Result: Bi = 0.01 — lumped capacitance valid
A steel plate (k = 50 W/mK) with Lc = 10 mm and h = 50 W/m²K gives Bi = 0.01. Since Bi < 0.1, the body is nearly isothermal and lumped analysis is appropriate.
Calculate the Biot number to determine if lumped capacitance analysis applies. Compare internal vs external thermal resistance for heat transfer problems. Use it when you need a repeatable calculation in the physics / general category and want the setup, result, and supporting values kept together. This is especially helpful when small input changes, unit choices, or rounding decisions can change the final number.
Start by confirming that the inputs match the formula shown on the page. Then compare the main output with the worked example and any secondary values shown by the calculator. If the result will be used in another calculation, keep extra precision until the final step and record the assumptions beside the number.
Treat the result as a calculation aid rather than a substitute for context. For schoolwork, include the formula and substitution steps. For planning, technical, financial, or health-related decisions, verify important numbers against primary records, current rules, or a qualified professional before acting on them.
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It is the ratio of internal conduction resistance to external convection resistance. Low Bi means heat conducts through the body much faster than it transfers to the surroundings.
When Bi < 0.1 — meaning the body's interior stays within about 5% of its surface temperature.
The surface approaches the fluid temperature quickly while the interior stays at the initial temperature — use Heisler charts or numerical methods.
Lc = Volume / Surface Area in general. For standard shapes: plate half-thickness, cylinder radius/2, sphere radius/3.
If h or k are temperature-dependent, Bi can vary. In most textbook problems, properties are assumed constant.
Both equal hL/k, but Biot uses the solid's conductivity and Nusselt uses the fluid's conductivity.
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