LMTD Calculator

Calculate the log mean temperature difference (LMTD) for heat exchangers in counterflow and parallel flow, with required area and effectiveness.

LMTD
79.58 °C
Log Mean Temperature Difference = (ΔT₁ − ΔT₂) / ln(ΔT₁/ΔT₂)
AMTD
80.00 °C
Arithmetic Mean Temperature Difference (always ≥ LMTD)
ΔT₁
90.00 °C
Thi − Tco
ΔT₂
70.00 °C
Tho − Tci
ΔT Ratio
1.286
ΔT₁ / ΔT₂ — closer to 1 means LMTD ≈ AMTD
Hot Fluid Drop
60.0 °C
Temperature decrease of the hot fluid
Cold Fluid Rise
40.0 °C
Temperature increase of the cold fluid
Required HX Area
2.513 m²
A = Q / (U × LMTD)
Effectiveness
46.2%
ε = (Thi−Tho) / (Thi−Tci)
Temperature Profile
150°
60°
← (counter)
90°
20°
ServiceU (W/m²·K)Notes
Water–Water800–1500Shell & tube
Steam–Water1000–6000Condensation
Gas–Gas10–40No phase change
Oil–Water100–350Shell & tube
Air–Water (forced)30–100Fin-tube coil
Steam–Oil50–350Shell & tube
Planning notes, formulas, and examples

About the LMTD Calculator

The Log Mean Temperature Difference (LMTD) is the driving force for heat transfer in a heat exchanger. It provides the effective average temperature difference between the hot and cold fluids, accounting for the fact that the temperature difference varies along the length of the exchanger. The LMTD is always less than or equal to the arithmetic mean temperature difference.

Heat exchangers are ubiquitous in engineering: condensers, evaporators, radiators, HVAC coils, oil coolers, and process heaters all rely on LMTD calculations for proper sizing. The fundamental design equation Q = U × A × LMTD connects the heat duty (Q), overall heat transfer coefficient (U), heat transfer area (A), and the LMTD.

This LMTD Calculator computes the LMTD for both counterflow and parallel-flow arrangements from the four terminal temperatures. It also calculates the arithmetic mean temperature difference, ΔT ratio, heat exchanger effectiveness, and the required surface area when U and Q are provided. Preset buttons cover common industrial applications, and a reference table provides typical U values for different fluid combinations.

When This Page Helps

Use this page to turn terminal temperatures into an effective heat-transfer driving force and then estimate exchanger area once duty and overall U are known. It keeps the temperature endpoints, LMTD, and area estimate together so the exchanger sizing step is easier to follow. That is useful when you want a quick sizing check before moving to a more detailed heat-exchanger model.

How to Use the Inputs

  1. Enter the hot fluid inlet and outlet temperatures.
  2. Enter the cold fluid inlet and outlet temperatures.
  3. Select the flow arrangement: counterflow or parallel flow.
  4. Enter the overall heat transfer coefficient U (W/m²·K) if known.
  5. Enter the heat duty Q (kW) if known.
  6. Review LMTD, AMTD, ΔT ratio, effectiveness, and required area.
  7. Consult the U value reference table for your fluid combination.
Formula used
LMTD = (ΔT₁ − ΔT₂) / ln(ΔT₁ / ΔT₂) Counterflow: ΔT₁ = Thi − Tco, ΔT₂ = Tho − Tci Parallel Flow: ΔT₁ = Thi − Tci, ΔT₂ = Tho − Tco Heat Transfer: Q = U × A × LMTD Area: A = Q / (U × LMTD)

Example Calculation

Result: LMTD = 76.1°C, AMTD = 80°C

A counterflow heat exchanger with hot fluid cooling from 150 to 90°C and cold fluid heating from 20 to 60°C has an LMTD of 76.1°C.

Tips & Best Practices

  • Counterflow usually delivers a larger LMTD than parallel flow for the same terminal temperatures, which is why it is common in compact exchanger design.
  • If one end temperature difference gets very small, area requirements can grow quickly even when the total heat duty looks modest.
  • Phase-change exchangers often simplify one side of the temperature profile because that stream stays nearly isothermal.
  • Cross-flow and multipass units usually need a correction factor rather than the plain counterflow or parallel-flow expression alone.

What LMTD Represents

LMTD is the effective average temperature difference that drives heat transfer through the exchanger. Because that driving force changes from one end of the exchanger to the other, a simple arithmetic mean usually misstates the true average.

Design Use

Once duty, U value, and LMTD are known, the required area follows directly from Q = U x A x LMTD. That makes LMTD one of the core screening tools in preliminary exchanger sizing, long before you build a full thermal design package.

When The Simple Form Needs Help

Pure counterflow and parallel-flow formulas are the cleanest cases. Shell-and-tube multipass units, cross-flow exchangers, and arrangements with leakage or bypass need a correction factor or an effectiveness-NTU approach instead of relying on raw LMTD alone.

Sources & Methodology

Last updated:

Frequently Asked Questions

  • Because the logarithmic mean correctly accounts for how the temperature difference changes along the exchanger length. The arithmetic mean ignores that changing profile, so it usually overstates the driving force.