Torsional Stiffness Calculator

Calculate torsional stiffness (k = GJ/L) for shafts, springs, and torsion bars. Includes deflection, natural frequency, and length comparison table.

MPa (79300 steel, 26000 Al)
mm
mm (0 for solid)
mm
N·m
Torsional Stiffness
3.80 N·m/rad
k = GJ/L
Angular Deflection
1,507.2299°
26.306124 rad
Natural Frequency
0.31 Hz
For 1 kg·m² rotor: f = √(k/I)/(2π)
Polar Moment (J)
38,350 mm⁴
π(D⁴−d⁴)/32
Series (2 shafts)
1.90 N·m/rad
1/k_total = 1/k₁ + 1/k₂
Parallel (2 shafts)
7.60 N·m/rad
k_total = k₁ + k₂
Stiffness vs Length
Short↑ Higher kLong
Stiffness vs Length
Length (mm)Stiffness (N·m/rad)Deflection (°)
20015.21376.8075
4007.60753.6150
6005.071,130.4224
8003.801,507.2299
1,2002.532,260.8449
1,6001.903,014.4598
2,4001.274,521.6897
Planning notes, formulas, and examples

About the Torsional Stiffness Calculator

Torsional stiffness measures how much torque is needed to twist a shaft by one radian: k = GJ/L, where G is the shear modulus, J is the torsional constant, and L is the shaft length. Higher stiffness means less angular deflection under load — critical for drive shafts, coupling hubs, and precision positioning systems.

The relationship is directly analogous to linear spring stiffness (k = EA/L for axial, k = F/x for springs). Doubling the diameter increases torsional stiffness by 16× (since J scales as D⁴), while doubling the length halves it. This strong diameter dependence means that small increases in shaft size dramatically reduce twist.

Torsional stiffness also determines natural frequency: a shaft with a flywheel at one end oscillates at f = √(k/I)/(2π). If this frequency matches an excitation source (engine RPM, gear mesh), resonance causes dangerous vibrations. It gives stiffness, deflection, natural frequency, and series/parallel combinations for system design.

When This Page Helps

Use this calculator when you need to estimate how much a shaft, torsion bar, or coupling will twist under load. It is useful for drivetrain sizing, suspension design, and any system where rotational deflection matters more than simple strength.

How to Use the Inputs

  1. Choose input mode: from shaft geometry (G, D, L) or direct stiffness value.
  2. For geometry mode: enter shear modulus, diameters, and length.
  3. Enter the applied torque to see angular deflection.
  4. Review stiffness, deflection, natural frequency, and series/parallel values.
  5. Use the length table to explore how shaft length affects stiffness.
Formula used
k = GJ/L (N·m/rad). θ = T/k (rad). Natural frequency: f = √(k/I)/(2π) Hz. Series: 1/k_total = Σ(1/kᵢ). Parallel: k_total = Σkᵢ.

Example Calculation

Result: k = 3,800 N·m/rad, deflection = 1.51°

A 25mm solid steel shaft, 800mm long: J = π(25)⁴/32 = 38,350 mm⁴. k = 79,300 × 38,350 / 800 / 10⁶ ≈ 3,800 N·m/rad. Under 100 N·m: θ = 100/3800 = 0.0263 rad = 1.51°.

Tips & Best Practices

  • Hollow shafts save weight with minimal stiffness loss — removing 50% core area reduces J by only 6%.
  • Torsion bar suspensions (used in trucks and military vehicles) size the bar to achieve desired spring rate.
  • For vibration avoidance, keep natural frequency at least 20% away from any excitation frequency.
  • Series connections (shafts end-to-end) reduce total stiffness; parallel connections increase it.

Shaft Stiffness Notes

Rotational stiffness is usually governed by geometry first and material second, so diameter and length changes often matter more than small material swaps.

Unit Conversion Errors

The most common errors are mixing units for G, J, and L or forgetting that a hollow shaft changes J far more than a small material change would.

Sources & Methodology

Last updated:

Frequently Asked Questions

  • The torque required to twist a shaft by one radian: k = T/θ = GJ/L. Units are N·m/rad or lb·in/rad. Higher k means stiffer — less twist for the same torque.