Calculate elastic and inelastic collision outcomes. Find final velocities, kinetic energy loss, and momentum conservation for two-body collisions and explosions.
The law of conservation of momentum states that the total momentum of an isolated system remains constant before and after a collision: m₁v₁ + m₂v₂ = m₁v₁' + m₂v₂'. This principle applies whether the event is a textbook cart collision, a billiards shot, or a crash-analysis estimate.
This calculator handles elastic collisions, partially inelastic collisions, and explosion-style separation problems. For inelastic impacts, you can set the coefficient of restitution (0 = perfectly inelastic, 1 = elastic) to model how much relative speed is preserved after contact. Outputs include final velocities, a momentum check, and kinetic-energy change.
Presets cover common teaching and engineering scenarios such as pool balls, head-on impacts, bullet-into-block problems, and Newton's cradle. The before-versus-after tables make it easier to compare what momentum conservation guarantees and what kinetic energy does not.
Momentum problems are simple in principle but easy to mishandle once sign conventions, unequal masses, or partially elastic impacts enter the picture. A small algebra slip can flip the direction of motion or hide how much kinetic energy was lost.
This calculator keeps the collision type, restitution setting, and energy accounting together so you can test scenarios quickly and still see the physical meaning of the result.
p = m₁v₁ + m₂v₂ (conserved). Elastic: v₁' = ((m₁-m₂)v₁ + 2m₂v₂)/(m₁+m₂). Inelastic with restitution e: v₁' = (m₁v₁ + m₂v₂ + m₂e(v₂-v₁))/(m₁+m₂). Perfectly inelastic (e=0): v' = (m₁v₁ + m₂v₂)/(m₁+m₂).
Result: v₁' = 0 m/s, v₂' = 2 m/s
Two equal-mass pool balls: the cue ball stops and the target ball moves away at the cue ball's original speed. This perfect momentum and energy transfer is characteristic of equal-mass elastic collisions.
Elastic collisions preserve total kinetic energy — translational motion is fully transferred between objects. Inelastic collisions convert some kinetic energy to thermal energy, sound, and permanent deformation. The coefficient of restitution (e) quantifies this: e = (v₂' − v₁') / (v₁ − v₂). Real car crashes have e ≈ 0.1–0.3; baseball bat hits have e ≈ 0.5.
Momentum conservation is one of three fundamental conservation laws in classical mechanics, alongside energy conservation and angular momentum conservation. Each corresponds to a symmetry: momentum conservation arises from translational symmetry (physics is the same everywhere in space), per Noether's theorem.
Forensic engineers use momentum conservation to reconstruct vehicle crashes. Pre-crash speeds are calculated from post-crash trajectories and deformation. Combined with skid mark analysis and energy methods (crush energy), momentum analysis provides court-admissible speed estimates with typical accuracy of ±10%.
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In elastic collisions, both momentum AND kinetic energy are conserved — objects bounce off perfectly. In inelastic collisions, momentum is conserved but kinetic energy is lost to heat, sound, and deformation. Most real collisions are inelastic.
The coefficient of restitution (e) measures how "bouncy" a collision is: e = 1 for perfectly elastic, e = 0 for perfectly inelastic (objects stick together), and 0 < e < 1 for real collisions. A rubber ball on concrete has e ≈ 0.8; a car crash has e ≈ 0.1-0.3.
Not macroscopically — all real collisions lose some energy. However, collisions between hard billiard balls (e ≈ 0.95), steel ball bearings, and subatomic particles come very close. At the atomic level, gas molecule collisions are effectively elastic.
Total momentum is zero before the collision (equal and opposite momenta). Conservation of momentum requires zero total momentum after — so in a perfectly inelastic collision, both cars stop, and ALL kinetic energy is lost to deformation. This is the most destructive collision type.
A bullet embeds in a block (perfectly inelastic collision). By measuring the block's velocity after impact, you can calculate the bullet's original speed: v_bullet = (m_bullet + m_block) × v_after / m_bullet. The energy "lost" goes into heat and deformation of the block.
Yes, in an isolated system (no external forces). Gravity, friction, and other external forces transfer momentum to/from the system, but during the brief collision event, external forces are negligible compared to impact forces, so momentum is effectively conserved.