Inductor Energy Calculator

Calculate energy stored in an inductor using E = ½LI². Includes time constant, inductive reactance, impedance, and L/R current rise visualization.

H
A
For time-constant analysis
V
Ω
For reactance calculation
Hz
Stored Energy
0.125000 J
E = ½LI²
Energy (mJ)
125.000 mJ
125,000.0 μJ
Time Constant (τ)
1.000 ms
τ = L/R
Inductive Reactance
62.83 Ω
X_L = 2πfL at 1000 Hz
Impedance |Z|
63.62 Ω
√(R² + X_L²)
Steady-State Current
1.200 A
V/R = 12/10
Steady-State Energy
7.200 mJ
½L(V/R)²
Initial di/dt
1,200.0 A/s
V/L at t=0

Current Rise (L/R Circuit)

0.5τ
39.3%
1τ
63.2%
2τ
86.5%
3τ
95.0%
4τ
98.2%
5τ
99.3%

Common Inductor Types

TypeTypical ValueApplication
Air-core solenoid1–100 μHRF circuits
Ferrite-core inductor10 μH – 10 mHPower supplies, filters
Toroidal inductor1–100 mHAudio, power electronics
Iron-core choke0.1–10 HPower line filtering
Superconducting coil (SMES)1–100 HEnergy storage
Planning notes, formulas, and examples

About the Inductor Energy Calculator

An inductor stores energy in its magnetic field when current flows through it. The energy stored is E = ½LI², where L is the inductance in henries and I is the current in amperes. This energy is released when the current decreases, which is why inductors resist changes in current — they are the electrical analog of mechanical inertia.

This Inductor Energy Calculator computes the stored energy from inductance and current values. It also analyzes the L/R time constant (how quickly current rises or falls in an inductive circuit), the inductive reactance at a given frequency, and the total impedance of a series R-L circuit. A current-rise visualization shows how the current approaches its steady-state value over multiple time constants.

Use it to size a relay coil, estimate the energy available in a switching converter inductor, or check how a coil responds to AC and transient changes in current.

When This Page Helps

Inductor problems often mix DC energy, AC reactance, and transient response in the same circuit. This calculator keeps those relationships together so you can see stored energy, current rise time, and frequency response without juggling separate formulas.

How to Use the Inputs

  1. Enter the inductance (L) in henries. Use decimal values for mH (e.g., 0.01 for 10 mH).
  2. Enter the current (I) flowing through the inductor in amperes.
  3. Optionally enter supply voltage and series resistance for time-constant analysis.
  4. Enter a frequency for inductive reactance calculation.
  5. Review stored energy, time constant, reactance, and impedance.
  6. View the current rise chart to see how current approaches steady state.
  7. Consult the inductor types reference table for typical applications.
Formula used
Stored Energy: E = ½ × L × I² Time Constant: τ = L / R Inductive Reactance: X_L = 2πfL Impedance: |Z| = √(R² + X_L²) Current Rise: I(t) = (V/R)(1 − e^(−t/τ)) Where: L = inductance (H) I = current (A) R = resistance (Ω) f = frequency (Hz)

Example Calculation

Result: 0.125 J (125 mJ)

An inductor with L = 10 mH carrying 5 A stores E = ½ × 0.01 × 25 = 0.125 J (125 mJ) of energy in its magnetic field.

Tips & Best Practices

  • Double the current quadruples the stored energy (E ∝ I²).
  • Flyback diodes are essential when switching inductive loads to suppress voltage spikes.
  • The time constant τ = L/R; increasing L or decreasing R makes current rise slower.
  • At DC (f = 0), an ideal inductor has zero reactance — it acts as a short circuit.
  • In switching power supplies, inductor energy storage and release is the core operating principle.

Magnetic Energy Storage

The energy stored in an inductor resides in its magnetic field. The energy density of a magnetic field is u = B²/(2μ₀), and integrating over the volume of the inductor gives E = ½LI². This is analogous to the energy stored in a capacitor (E = ½CV²) and in a spring (E = ½kx²) — all are quadratic in the relevant state variable.

L/R Circuits and Transient Response

When a DC voltage is applied to a series RL circuit, the current rises exponentially: I(t) = (V/R)(1 − e^(−t/τ)). The time constant τ = L/R determines the speed of this rise. Large inductors with small resistance take longer to reach steady state. This transient behavior is critical in relay timing, motor starting, and power supply design.

Applications in Power Electronics

Inductors are fundamental components in switching power supplies (buck, boost, buck-boost converters), where they alternately store and release energy each switching cycle. The inductance value, saturation current rating, and core losses determine converter performance. Proper inductor selection is often the most critical design decision in a power supply.

Sources & Methodology

Last updated:

Frequently Asked Questions

  • Current flowing through an inductor creates a magnetic field. Energy is stored in this field. When the current is interrupted, the collapsing field releases the stored energy, often producing a voltage spike.